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120x^2-116x-28=0
a = 120; b = -116; c = -28;
Δ = b2-4ac
Δ = -1162-4·120·(-28)
Δ = 26896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{26896}=164$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-116)-164}{2*120}=\frac{-48}{240} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-116)+164}{2*120}=\frac{280}{240} =1+1/6 $
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